Volume calculation & Air circulation

In order to ensure the best possible capture of aerosols, viruses and other particles, the calculation of the room volume is fundamental. In combination with the appropriate air circulation (6-fold recommended) and the correct air circulation ("downflow" principle), it is assumed, according to Prof. Dr. Christian Kähler, that no aerosol concentration of infectious level can be generated.

Both the 360° arranged and flow-optimised air intake slots and the various air outlets ensure the best possible air intake and, above all, air distribution in the room. These allow rooms to be optimally flooded with safe and clean air according to their nature.

Volume calculation & required air volume

A room with a width of approx. 7 metres, a depth of approx. 10 metres and a height of approx. 2.5 metres has a volume of approx. 175 m³.

This volume should be circulated at least approx. 6 times/hour. This results in a required air volume of approx. 1,050 m³/h.

Width x depth x height = room volume
7 x 10 x 2.5 metres = 175 m³

Room volume x circulation = Actual volume flow required
175 m³ x 6 /h = 1,050m³/h

Width x depth x height x circulation = actual volume flow required
7 x 10 x 2.5 m³ x 6/h = 1,050m³/h

Circulationlateral - not complete
ResultNot suitable
Intake top
Blow-out downstairs
Circulation upwards - not complete
Result Not suitable
Circulationlateral - not complete
ResultNot suitable
Circulationcomplete room circulation
ResultSuitable and recommended

Optimum air intake and distribution

  • Version 360° (as delivered)
    Set up in the centre of the room > Air is distributed in all directions
  • Corner version
    Unit in corner of room > Air is distributed in 3 directions
  • Spigot version
    Top version with pipe spigot > the exhaust air is blown in via a pipe e.g. into a central ventilation system
270° wide
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